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In going through a gate it is important to keep a same-side focus with all project stakeholders. Their critique of the correctness of the project work to date, and their re-evaluation of project value, is not a criticism of you, your work, or your team. Rather, it is a supportive process that ensures that the team and the customer are still on the same page. Sometimes, needs change, and project changes are required in response. Sometimes, misunderstandings are discovered. Leave your ego at the door, and be ready to learn from and work with your customers. Going through a gate is a process that takes time. Table 4-3 shows the deliverables and steps for each gate. As we mentioned above, it is thoroughly appropriate to cancel a project at the gate at the end of the concept stage. We hope that any project that makes it through the concept stage will succeed. However, if we see that a project will never deliver value greater than cost, we should stop before too much money is wasted. Therefore it can be appropriate to end a project at any gate.

If we set y = 0 and then solve the resulting quadratic equation, we get two roots that tell us the x-intercepts of the curve The roots here can be read straight from the factors as x=1 or x=2 revealing that (1,0) and (2,0) lie on the parabola These two points are close together, and they re also close to the vertex It s difficult to draw a good image of the parabola based on these three points alone But we can find the y-intercept, which is farther out, to help us draw the curve When we plug in 0 for x, we get y = 02 3 0 + 2 = 0 0 + 2 = 2 indicating that (0,2) is on the parabola Now that we know the coordinates of four points that lie on the parabola, we can do some mental curve-fitting and sketch the graph as shown in Fig B-12

Since the temperature of the flame falls with either an excess or a deficiency of air, it is not a particularly good controlled variable The most universally used indication of combustion efficiency is a measurement of oxygen content in the combustion products The amount of excess air required to ensure complete combustion depends on the nature of the fuel iSatura1 gas, for example, can be burned efficiently with 8 to 10 percent excess air (16 to 2 percent excess oxygen), while oil requires 10 to 15 percent excess air (2 to 3 percent excess oxygen) and coal, 18 to 25 percent excess air (35 to 5 percent excess oxygen) The reasons for the differences are the relative state of the fuel and the amount of noncombustibles present.

(0, 2)

Evaluation steps Is there support for the concept Does the plan o er enough value Does the approach t the company Are costs in line with value and with available resources Are the delivery date and sta allocations useful to the company Is the overall level of risk acceptable Is there support for the project Does value exceed cost Is the schedule acceptable Does this meet the customer s needs Is it what they want Will the new product or service t into the company Is everyone included Will everyone sign on Have all major risks been identi ed Are stakeholders con dent risk can be managed and the team can succeed Is the schedule acceptable Are resources available to do the work Is cost acceptable Have all risks been identi ed Are risks, mitigation plans, and contingency plans acceptable Is quality plan acceptable

(1, 0) x (2, 0) (3/2, 1/4)

Figure B-12

13

Table 4-3 Deliverables and steps for each gate (Continued).

10 The standard-form general equation for a hyperbola in the xy plane is (x x0)2 /a2 (y y0)2 /b2 = 1 where (x0,y0) are the coordinates of the center, a is the length of the horizontal semi-axis, and b is the length of the vertical semi-axis The specific equation of our hyperbola is (x 1)2 /4 (y + 2)2 /9 = 1 From this equation, we can see that the constants are x0 = 1 y0 = 2 a = 41/2 = 2 b = 91/2 = 3 This information tells us that the hyperbola s center is at (1, 2) The horizontal semiaxis is 2 units wide The vertical semi-axis is 3 units tall We can therefore sketch the graph as shown in Fig B-13